Robert Koslover
Certified Consultant
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Posted:
6 months ago
2024年2月26日 GMT+1 23:53
Updated:
6 months ago
2024年2月27日 GMT+1 00:01
Your model didn't include ameshor astudy, both of which are needed to execute the model. So I took a wild guess and added a default mesh and a simple stationary study, then executed the model. (Note that these arenotnecessarily the best mesh or study for you.) Anyway, it completed without error messages. I'm not sure what impedance you are looking for, but I computed the terminal voltage / terminal current, which has units of resistance. See the attached edited version of your model. I cleared the solution (which is not the same as deleting the solver) to make the file small enough to upload. In principle, all you need to do is execute this file on your computer (push that big equal-sign button with the word "Compute" on it) and the solution will be there in the Results section. Result is about 1.225 x 10^-4 Ohms. Hope this helps. Note: I wouldn't simply trust that result without (at least) more careful attention to the mesh, by the way.
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Scientific Applications & Research Associates (SARA) Inc.
www.comsol.com/partners-consultants/certified-consultants/sara
Your model didn't include a *mesh* or a *study*, both of which are needed to execute the model. So I took a wild guess and added a default mesh and a simple stationary study, then executed the model. (Note that these are *not* necessarily the best mesh or study for you.) Anyway, it completed without error messages. I'm not sure what impedance you are looking for, but I computed the terminal voltage / terminal current, which has units of resistance. See the attached edited version of your model. I cleared the solution (which is not the same as deleting the solver) to make the file small enough to upload. In principle, all you need to do is execute this file on your computer (push that big equal-sign button with the word "Compute" on it) and the solution will be there in the Results section. Result is about 1.225 x 10^-4 Ohms. Hope this helps. Note: I wouldn't simply trust that result without (at least) more careful attention to the mesh, by the way.